Wednesday 10 April 2013

Write a C program to calculate Sum=1-x2/2!+ x4/4!- x6/6!+ x8/8!- x10/10!



Write a C program to calculate the following Sum:
Sum=1-x2/2!+ x4/4!- x6/6!+ x8/8!- x10/10!





Program:
#include <math.h>
void main()
{
int counter,f_coun;float sum=0,x,power,fact;
clrscr();
printf("<--------------------PROGRAM FOR SUM OF EQ.SERIES----------------------->");
printf("\n\n\tEQUATION SERIES : 1-X^2/2! + X^4/4! -X^6/6! + X^8/8! -X^10/10!");
printf("\n\n\n\tENTER VALUE OF X : ");
scanf("%f",&x);
for(counter=0, power=0; power<=10; counter++,power=power+2)
{
fact=1; 
//CALC FACTORIAL OF POWER VALUE
for(f_coun=power; f_coun>=1; f_coun--)
fact *= f_coun;
 //EQ. FOR SUM SERIES
sum=sum+(pow(-1,counter)*(pow(x,power)/fact));
}
printf("SUM : %f",sum);
getch();
}

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