c program to caculate Sum=1-x2/2!+ x4/4!- x6/6!+ x8/8!- x10/10!

 To calculate the sum. Sum=1-x²/2!+ x⁴/4!- x⁶/6!+ x⁸/8!- x¹⁰/10!

 Using non-recursion

 Main program:

Step 1: start

Step 2: declare x,i,n,s=0,c

Step 3: read x value

Step 4: for i=0 , n=0; i<=10; i=i+2, n++ goto step 5

Step 5: s=s+(pow(-1,n)*pow(x,i)/fact(i))

Step 6: print s value

Step 7: stop

 Sub program:

Step 1: while x!=0 goto Step 2

Step 2: y=y+x; x—

Step 3: return y

Step 4: return to main program

#include<stdio.h>

#include<math.h>

long fact(int);

void main()

 {

            int x,i,n;

              float s=0,c;

             clrscr();

             printf("\n enter the value of x\t");

            scanf("%d",&x);

/*perform the looping operation*/

              for(i=0,n=0;i<=10;i=i+2,n++)

            s=s+(pow(-1,n)*pow(x,i)/fact(i));

             printf("\n the result is %f",s);

             getch();

 }

/* calling sub program*/

long fact(int x)

{

            long int y=1;

            while(x!=0)

            {

                         y=y*x;

                         x--;

            }

             return y;

}